Quick math question!

The Playing Zone
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Yea please :pray:

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Because you too smart to join

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Yup

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And actually everyone can understand that math

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Ok gtg to bed bye

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Oh your time is 9:23…Oh fine

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I don’t know why but this look wrong

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uhhh 1. axa = 8

  • If we assume axa = a^2**, then you’re right that no integer squared equals 8. For example, (2^2 = 4) and (3^2 = 9), so there’s no integer (a) such that (a^2 = 8).
  1. axb = 16
  • If A can’t be any number that makes sense in the context of axa = 8**, then finding A and B such that axb = 16 might be tricky. However, if we consider a and b as different variables, we can find pairs that satisfy this equation. For example, if (a = 2) and (b = 8), then (2 \times 8 = 16).
  1. bxb:
  • If bxb means (b^2), then we can solve for (b) such that (b^2 = 16). In this case, (b = 4) or (b = -4).
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axa=8

axb=16

bxb= 32

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AREN’T THESE VARIABLES
i hate variables lol-
Capture

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yeah

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congratulations @AyoBird !

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My mind is hurting just looking at this…

Why?

Idk

Is there something wrong…

No… Maybe

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Ayobird…You REAL SMART…Ohh…I forgot everyone is smart except me

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Thanks

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No don’t just say everyone better cuz we got same values

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what is the value of 8^5 the answer will be revealed tomorrow

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Huh

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its HARD

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Right